# Re: linking (jumping) from line of code to an other

 The Solution is: Using whil: ```i = 1 a = 1 while i < 5 disp(i) a = a + 1 i = i +1 if a == 3 then i = i - 1 end end```   Am 2017-05-12 11:15, schrieb Frieder Nikolaisen: Hello, another question to solve the locomotive stuff, giving you a example with the not implented code.  I don't want to code the same stuff twice. Thats why I want to jump between lines of code. Is this possible and how?  ```P = 200; DM = 1; for n = 1:10 if DM == 1 then if P > 100 then DM = 1 P = P - 60 disp('P bigger 100. DM = ' + string(DM)) else DM = 0 P = P + 100 //instead of writing P = P + 100, I would like ... disp('P smaller 100. DM = ' + string(DM)) end else // D == 0 if P > 100 then DM = 1 disp('P bigger 100. DM = ' + string(DM)) P = P - 30 else DM = 0 // ... to continue here disp('P smaller 100. DM = ' + string(DM)) P = P + 100 // to use this P = P + 100 end end disp(string(n) + ' ' + string(P)) end```       _______________________________________________ users mailing list [hidden email] http://lists.scilab.org/mailman/listinfo/users