[Scilab-users] Triple integral (int3d) query

Hello all,

I have worked out a simpler input for 2D integration with a function that
calls int2d:

function [Integral, error]=Integral_2d(xmin,xmax,ymin,ymax,f)
    X=[xmin xmax xmax; xmin xmax xmin]'
    Y=[ymin ymin ymax; ymin ymax ymax]'
    [Integral, error]=int2d(X,Y,f)
endfunction

This simplifies the issue for triangulation and only needs the x, y limits
and function to integrate; tested with the int2d example and works fine.

Is it feasible to use the same methodology for int3d - triple integral - for
defining the tetrahedron vertices? Really all one wants to do is enter the
limits of x, y and z, with a function f(x,y,z).

Any suggestions would be welcome

Lester



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Hello all,

I have worked out a simpler input for 2D integration with a function that
calls int2d:

function [Integral, error]=Integral_2d(xmin,xmax,ymin,ymax,f)
    X=[xmin xmax xmax; xmin xmax xmin]'
    Y=[ymin ymin ymax; ymin ymax ymax]'
    [Integral, error]=int2d(X,Y,f)
endfunction

This simplifies the issue for triangulation and only needs the x, y limits
and function to integrate; tested with the int2d example and works fine.

Is it feasible to use the same methodology for int3d - triple integral - for
defining the tetrahedron vertices? Really all one wants to do is enter the
limits of x, y and z, with a function f(x,y,z).

Any suggestions would be welcome

With Scilab 6.0.2 you can install the CGLAB toolbox atomsInstall("cglab"). Then its delaunay_3() function will yield tetrahedrons required by int3d(). An intermediate step might be required to specify tetrahedrons in the way that int3d() expects.

Best wishes and Happy New Year 2021 to you, and to all Scilab users!

Samuel

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Hi Samuel,

Many thanks for the suggestion. Happy New Year to you too.

Kind regards
Lester



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